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81 D The mass should be 226 (4 + 4 + 0 + 4) = 214 The atomic number should be 88 (2 + 2 1 + 2) = 83 82 C Alpha particles are the least penetrating, and gamma rays are the most penetrating 83 C Mass difference = 236 4(1) 136 = 96 Atomic number difference = 92 4(0) 53 = 39 84 C After one half-life, 50% would remain After another half-life this would be reduced by 1 2 to 25% The total amount decayed is 75% Thus, 246 years must be two half-lives of 123 years each

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The bits of a G7231 frame are formatted as shown in Figures 6-13 and 6-14 (see Tables 5/G7231 and 6/G7231) Within the fields of a data unit, later octets are more significant This is based on H324 bit order assignment and is the reverse of the RFC 791 convention With each octet, the bits are with the MSB on the left and the LSB on the right A G7231 encoded voice subframe consists of a single audio frame; the audio frame (30 ms per frame) is packetized into 20 or 24 octets

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Because of the importance of glucose as the basic coin of cellular energy exchange and the prevalence of diabetes, which manifests itself as renal disease along with other pathologies, we review the normal renal handling of glucose The normal plasma glucose level is about 90 mg/dL (5 mmol/L) It rises transiently to well over 100 mg/dL during meals and can reach levels of over 1000 mg/dL (over 55 mmol/L) in severe diabetes Normally, all the filtered glucose is reabsorbed in the proximal tubule This involves removing glucose from the tubular lumen along with sodium via a sodium-dependent glucose symporter (SGLUT) across the apical membrane of proximal convoluted tubule epithelial cells, followed by its exit across the basolateral membrane into the interstitium via a GLUT uniporter Unlike the case for sodium and many other solutes discussed later, the tight junctions are not significantly permeable to glucose Therefore, as glucose is removed from the lumen and the luminal concentration falls, there is no back-leak The transport of a solute with no back-leak depends only on the characteristics of the rate-limiting transporter, in this case the SGLT symporter, and is a Tm-limited system Because glucose reabsorption is a Tm system, abnormally high filtered loads overwhelm the reabsorptive capacity (exceed the Tm; Figure 5 1) This occurs when plasma glucose rises above roughly 300 mg/dL Again, this is a pathological situation but one that is relatively common Assume that the glucose Tm is 375 mg/min (a typical value) The normal filtered load is well below this level With a glomerular filtration rate (GFR) of 125 mL/min (125 dL/min) and plasma glucose of 90 mg/dL, the filtered load is 125 dL/min 3 90 mg/dL 5 1125 mg/min, much less than the Tm of 375 mg/min When plasma glucose reaches 300 mg/dL, the filtered load is now 125 dL/min 3 300 mg/dL 5 375 mg/min At this point, the proximal convoluted tubule fails to reabsorb all the filtered glucose, and a little glucose begins to spill into the urine Further increases in plasma glucose above 300 mg/dL lead to progressively greater renal losses We discuss the various reasons for the diuresis (high urine volume) associated with diabetes later, but one can appreciate that any glucose not reabsorbed is an osmole in the tubule that has consequences for water reabsorption.

Now that you have finished and scored the diagnostic exam, it is time for you to learn what it all means First, note any area where you had difficulty This should not be limited to unfamiliar material You should do this even if you got the correct answer Determine where this material is covered in the book Plan to spend additional time on the chapter in question There is material you may not recognize because you have not gotten that far in class The following relation determines the baseline score N represents the number of answers Ignore those you left blank (Ncorrect 1/4 Nincorrect = raw score for the multiple-choice section) There are no free-response questions on this diagnostic exam; such questions are not useful at this point There will be examples of free-response questions later in this book We will use the multiple-choice questions to provide an estimate of your preparation This is a simplified approach based on these questions Do not try to do more than use these results as a guide Raw Score 50 86 37 49 27 36 16 26 0 15 Approximate AP Score 5 4 3 2 1

66 / 5

0 1 2 3 4 5 6 0 7 0

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